FactorisingFactorise algebraic expressions in this structured online self marking exercise. 
This is level 1: factorising an expression with a constant factor. You can earn a trophy if you get at least 9 questions correct and you do this activity online.
Order the terms in your answers in the same order as they appear in the question.
This is Factorising level 1. You can also try:
HCF
Level 2
Level 3
Level 4
Level 5
Level 6
Level 7
Level 8
Level 9
More Quadratics
Expanding Brackets
More Algebra
InstructionsTry your best to answer the questions above. Type your answers into the boxes provided leaving no spaces. As you work through the exercise regularly click the "check" button. If you have any wrong answers, do your best to do corrections but if there is anything you don't understand, please ask your teacher for help. When you have got all of the questions correct you may want to print out this page and paste it into your exercise book. If you keep your work in an ePortfolio you could take a screen shot of your answers and paste that into your Maths file. 




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Level 1  Factorising an expression with a constant factor.
Example: 40h + 88
Level 2  Factorising an expression with a variable factor.
Example: 23h + 3h²
Level 3  Factorising an expression with both a constant and variable factor.
Example: 10a + 2ab
Level 4  Completely factorising an expression of two parts that can be separately factorised.
Example: 3a + ab + 5w + 4wy
Level 5  Writing an expression as the product of two binomials.
Example: 5a + 5b + ac + bc
Level 6  Factorising an expression which is the difference between two squares.
Example: c²  81
Level 7  Factorising a quadratic where the squared term coefficient is 1.
Example: c²  13c + 36
Level 8  Factorising a quadratic where the squared term coefficient is not 1.
Example: 4a² + 5a  6
Level 9  Mixed factorisation questions
Example: b² + 6b + 9
Projectable large format factorising quadratics exercise suitable for whole class use.
This program checks your answers by matching the text you have typed in with the options it has as the correct answer. For that reason it does not always recognise equivalent correct answers. For example the factorisation of 6a+21 can be written as 3(2a+7) or 3(7+2a) but the program may only recognise the first option as the correct answer. Please type in your answers so that the terms are in alphabetical order of the variables followed by the constants unless a negative cooeficient of the viariable makes the opposite a more elegant solution.
Identify a common factor of 8 to give \(8(5h+11)\)
Identify a common factor of h to give \(h(23+3h)\)
Identify a common factor of 2a to give \(2a(5+b)\)
Identify common factors of pairs of terms to give \(a(3+b)+w(5+4y)\)
Extract common factors of pairs of terms to give \(5(a+b) + c(a+b)\)
Then extract a common factor of (a+b) to give \((a+b)(5+c)\)
This can be written as \( (c+9)(c9) \). Expand the brackets to see why
Start by finding two numbers with a product of 36 and sum of 13
These numbers are 4 and 9
So the factorisation is \( (c4)(c9) \)
Multiply the coefficient of a² by the constant term: \( 4 \times 6 = 24 \)
Now find two numbers with a product of 24 and sum of 5 (the coefficient of a)
These numbers are 3 and 8
Write the original expression with the middle term split into these two numbers: \( 4a^23a+8a6\)
Extract common factors of pairs of terms to give \( a(4a3) + 2(4a3)\)
Then extract a common factor of (4a3) to give \((a+2)(4a3)\)
Use the techniques used in the previous levels
Don't wait until you have finished the exercise before you click on the 'Check' button. Click it often as you work through the questions to see if you are answering them correctly. You can doubleclick the 'Check' button to make it float at the bottom of your screen.
Answers to this exercise are available lower down this page when you are logged in to your Transum account. If you don’t yet have a Transum subscription one can be very quickly set up if you are a teacher, tutor or parent.
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Callum Arthur,
Tuesday, August 29, 2017