Iteration

Find approximate solutions to equations numerically using iteration.

FibonacciLevel 1Level 2Level 3Level 4Exam-StyleDescriptionHelpMore Algebra

This is level 2: rearranging equations. You can earn a trophy if you get at least 5 questions correct.

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 1. The equation $$x^2 - 4x + 3 = 0$$ can be arranged to give which of the following iterative formulas?$$x_n = \frac{x_{n-1}^2}{4} + \frac{3}{4}$$$$x_n = \frac{x_{n-1}^2}{4} - \frac{3}{4}$$$$x_n = \frac{x_{n-1}^2}{3} - \frac{4}{3}$$ 2. The equation $$x^2 - 5x + 7 = 0$$ can be arranged to give which of the following iterative formulas?$$x_n = \sqrt{5x_{n-1}+7}$$$$x_n = (5x_{n-1}-7)^2$$$$x_n = \sqrt{5x_{n-1}-7}$$ 3. The equation $$x^2 + 2x - 5 = 0$$ can be arranged to give which of the following iterative formulas?$$x_n = \frac{2}{5} - \frac{x_{n-1}^2}{5}$$$$x_n = \frac{5}{2} - \frac{x_{n-1}^2}{2}$$$$x_n = \frac{5}{2} + \frac{x_{n-1}^2}{2}$$ 4. The equation $$x^3 - x - 9 = 0$$ can be arranged to give which of the following iterative formulas?$$x_n = \sqrt{x_{n-1}-9}$$$$x_n = (x_{n-1}-9)^2$$$$x_n = \sqrt[3]{x_{n-1}+9}$$ 5. The equation $$x^2 + 5x - 2 = 0$$ can be arranged to give which of the following iterative formulas?$$x_n = \frac{2}{5} + \frac{x_{n-1}^2}{5}$$$$x_n = \frac{2}{5} - \frac{x_{n-1}^2}{5}$$$$x_n = \frac{5}{2} + \frac{x_{n-1}^2}{2}$$ 6. The equation $$x^3 - 2x^2 - 3 = 0$$ can be arranged to give which of the following iterative formulas?$$x_n = \sqrt[3]{2x_{n-1}-3}$$$$x_n = (2x_{n-1}^2-3)^2$$$$x_n = \sqrt[3]{2x_{n-1^2}+3}$$
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This is Iteration level 2. You can also try:
Level 1 Level 3 Level 4

Instructions

Try your best to answer the questions above. Type your answers into the boxes provided leaving no spaces. As you work through the exercise regularly click the "check" button. If you have any wrong answers, do your best to do corrections but if there is anything you don't understand, please ask your teacher for help.

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Description of Levels

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Fibonacci Probably the first iterative example learners will encounter is the Finonacci sequence. A simple rule exists for finding the next term of the sequence from the previous two.

Level 1 - Generating sequences using next term rule.

Level 2 - Rearranging equations.

Level 3 - Using flowcharts to define iterations.

Level 4 - Solving equations to one decimal place.

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Example

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For an animated demonstration of the calculator button pressing order for iteration see Calculator Workout skill 16.

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