## Real life problems adapted from an old Mathematics textbook (A First Book in Algebra, by Wallace C. Boyden 1895) which can be solved using algebra and common sense!

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This is level 7: the algebra involved in this level includes fractions. You can earn a trophy if you get at least 9 questions correct and you do this activity online.

 1. Roger is one-fourth as old as his father, and the sum of their ages is 70 years. How old is Roger? Working: 2. In a mixture of 360 bushels of grain, there is one-fifth as much corn as wheat. How many bushels of wheat were in the mixture? Working: 3. A bicyclist rode 105 miles in a day. If he rode one-half as far in the afternoon as in the forenoon, how fmany miles did he ride in the afternoon? Working: 4. What number is that which being diminished by one-seventh of itself will equal 162? Working: 5. Jane is one-fifth as old as Mary, and the difference of their ages is 12 years. How old is Mary? Working: 6. The fourth and eighth of a number are together equal to 36. What is the number? Working: 7. The half, third, and fifth of a number are together equal to 93. Find the number. Working: 8. A man left half his estate to his widow and a fifth to his daughter. If they both together received £28000, what was the value, in pounds, of his estate? Working: 9. Henry gave a third of his marbles to one boy, and a fourth to another boy. He finds that he gave to the boys in all 14 marbles. How many had he at first? Working: 10. A fruit-seller sold one-fourth of his oranges in the forenoon, and three-fifths of them in the afternoon. If he sold in all 255 oranges, how many had he at the start? Working: 11. Two women own a third and two-fifths of a mill respectively. If their part if the property is worth £22000, what is the value of the mill in pounds? Working: 12. A man spaded up three-eighths of his garden, and his son spaded two-ninths of it. In all they spaded 43 square rods. How large (in square rods) was the garden? Working:
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This is Algebra In Action level 7. You can also try:
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## Instructions

Try your best to answer the questions above. Type your answers into the boxes provided leaving no spaces. As you work through the exercise regularly click the "check" button. If you have any wrong answers, do your best to do corrections but if there is anything you don't understand, please ask your teacher for help.

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Learning and understanding Mathematics, at every level, requires learner engagement. Mathematics is not a spectator sport. Sometimes traditional teaching fails to actively involve students. One way to address the problem is through the use of interactive activities and this web site provides many of those. The Go Maths page is an alphabetical list of free activities designed for students in Secondary/High school.

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## Teachers

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Transum,

Sunday, January 26, 2014

"These questions have been adapted from 'A First Book in Algebra' by Wallace Boyden. They all are designed to encourage an algebraic solution by setting up an equation (or alternatively simultaneous equations) and solving it. Some of the questions could be classified under the topic of ratio.
In his introduction Wallace Boyden states 'Algebra is so much like arithmetic that all that you know about addition, subtraction, multiplication, and division, the signs that you have been using and the ways of working out problems, will be very useful to you in this study. There are two things the introduction of which really makes all the difference between arithmetic and algebra. One of these is the use of letters to represent numbers, and you will see in the following exercises that this change makes the solution of problems much easier.'."

I'm Not A Humanist But..., Planet Earth

Saturday, May 24, 2014

"On level 4 of the 'algebra in action' section, question 11 says:
"Divide the number 137 into three parts, such that the second is 3 more than the first, and the third five times the second. What is the third part?"
The answer is 100, but it was marked as being wrong, so I tried again, but with 20 (the second number) and 17 (the first number) and it marked 17 as being correct.

[Transum: Thank you so much for taking the time to highlight this error. You were indeed right and the error has now been corrected. Thank you so much.]"

Nick Staples, Waipahu Intermediate

Wednesday, August 18, 2021

"Is there a way these algebra in action activities can be made into printable worksheets please.

[Transum: Thanks for your feedback Nick. Most of the Transum online exercises can be printed directly from your browser. The input boxes transform into dotted lines for pupils to write their answers on and if the page is being printed by a Transum subscriber, the answers appear at the bottom of the worksheet.]"

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## Description of Levels

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Level 1 - Find two values given their ratio and either their sum or difference

Level 2 - Find one of three numbers given the connection between them

Level 3 - Find numbers whose sum and difference are given

Level 4 - Find numbers when given information about the sum or difference of their multiples

Level 5 - More questions similar to those in previous levels

Level 6 - Yet more questions similar to those in previous levels

Level 7 - The algebra involved in this level includes fractions

Answers to this exercise are available lower down this page when you are logged in to your Transum account. If you don’t yet have a Transum subscription one can be very quickly set up if you are a teacher, tutor or parent.

## Curriculum Reference

See the National Curriculum page for links to related online activities and resources.

Back in 1895 Mr Boyden wrote 'Algebra is so much like arithmetic that all that you know about addition, subtraction, multiplication, and division, the signs that you have been using and the ways of working out problems, will be very useful to you in this study. There are two things the introduction of which really makes all the difference between arithmetic and algebra. One of these is the use of letters to represent numbers, and you will see in the following exercises that this change makes the solution of problems much easier'.

## Example for level 7

Divide the number 72 into two parts such that one part shall be one-eighth of the other.
Let $$x$$ = larger part, then $$\frac{x}{8}$$ = lesser part.
$$x + \frac{x}{8} = 72$$
$$\frac{9x}{8} = 72$$
$$\frac{x}{8} = 8$$
$$x = 64$$
The parts are 64 and 8.

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