\( \DeclareMathOperator{cosec}{cosec} \)

Sign In | Starter Of The Day | Tablesmaster | Fun Maths | Maths Map | Topics | More

International Baccalaureate Mathematics

Calculus

Syllabus Content

Area of the region enclosed by a curve and the y-axis in a given interval.
Volumes of revolution about the x-axis or y-axis.

Here are some exam-style questions on this statement:

See all these questions

Click on a topic below for suggested lesson Starters, resources and activities from Transum.


Furthermore

Formula Booklet:

Area of region enclosed by a curve and y-axis

\( A = \int_{a}^{b} |x| dy \)

Volume of revolution about the x or y-axes

\( V = \int_{a}^{b} \pi y^2 dx \; \text{ or } \; V = \int_{a}^{b} \pi x^2 dy\)


The Volume of Revolution about the x-axis is a method used to find the volume of a solid obtained by rotating a region bounded by a function y=f(x), the x-axis, and two vertical lines x=a and x=b about the x-axis.

The formula for finding the volume of the solid is given by:

$$V = \pi \int_{a}^{b} (f(x))^2 , dx$$

where V represents the volume of the solid.

For example, let us find the volume of the solid obtained by rotating the region bounded by the function y=x and the x-axis about the x-axis from x=0 to x=1:

$$V = \pi \int_{0}^{1} (x)^2 , dx$$

Integrating the above expression, we get:

$$V = \pi \left[ \frac{x^3}{3} \right]_{0}^{1} = \frac{\pi}{3}$$

Therefore, the volume of the solid obtained by rotating the region bounded by the function y=x and the x-axis about the x-axis from x=0 to x=1 is \(\frac{\pi}{3}\).


How do you teach this topic? Do you have any tips or suggestions for other teachers? It is always useful to receive feedback and helps make these free resources even more useful for Maths teachers anywhere in the world. Click here to enter your comments.


Apple

©1997-2024 WWW.TRANSUM.ORG