Xavier and Jocelyn are both the same age.
Xavier multiplied his age by three, subtracted two then multiplied the answer by five.
Jocelyn multiplied her age by fourteen then added five
Xavier and Jocelyn arrived at the same answer as each other.
How old are Xavier and Jocelyn?
How did you use this starter? Can you suggest
how teachers could present or develop this resource? Do you have any comments? It is always useful to receive
feedback and helps make this free resource even more useful for Maths teachers anywhere in the world.
Click here to enter your comments.
If you don't have the time to provide feedback we'd really appreciate it if you could give this page a score! We are constantly improving and adding to these starters so it would be really helpful to know which ones are most useful. Simply click on a button below:
This starter has scored a mean of 3.8 out of 5 based on 115 votes.
Let Xavier and Jocelyn be x years old.
5(3x - 2) = 14x + 5
15x - 10 = 14x + 5
x = 15
Xavier and Jocelyn are both fifteen years old.
Note to teacher: Doing this activity once with a class helps students develop strategies. It is only when they do this activity a second time that they will have the opportunity to practise those strategies. That is when the learning is consolidated. Click the button above to regenerate another version of this starter from random numbers.
Teacher, do your students have
access to computers?
Here is the URL for a concise version of this page without comments or answers.
Here is the URL which will take them to a related activity.