Without a calculator copy and complete:
\(4\times3=12\)
\(3\times2 = 6\)
\(2\times1 =\)
\(1\times0 =\)
\(0\times1 =\)
\(1\times2 =\)
\(2\times\)
\(3\times\)
\(4\times\)
\(5\times\)
If a = 4, b = 2 and c = 6
find the values of:
\(a + b\)
\(ac\)
\(b  c\)
\(abc\)
\(a + b + c\)
\(bc^2\)
\((bc)^2\)
\(a^2b^3\)
\(c(b  a)\)
\(b^a\)
Topics: Starter  Negative Numbers  Number
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Previous Day  This starter is for 15 January  Next Day
4 x 3 = 12 
2 
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