Simplify this algebraic fraction

\( \frac{2^{x+1}}{2^{x-1}} \)

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Applying the laws of indices:

= \( \frac{2^x \times 2^1}{2^x \div 2^1} \)

Multiply numerator and denominator by \(2\).

= \( \frac{2^x \times 4}{2^x} \)

Divide numerator and denominator by \(2^x\).

= 4

More Mathematics Lesson Starters

Pauline Johnson, Preston, Lancashire

Wednesday, November 7, 2018

"I did this a different way by subtracting the indices. I did

2^(x+1)-(x-1). Then multiplying out the brackets we get 2^(x+1-x+1). The x's disappear and we are left with 2^2=4."

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