Nevaeh thinks of a number.
She then does the following operations:
Multiply by 2, subtract 4, multiply by 3 then add 28 (in that order).
She finds that the number she ends up with is 10 times her original number.
What was Nevaeh's original number?
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Previous Day  This starter is for 11 April  Next Day
This question is best answered by forming an algebraic equation then solving it. Let Nevaeh's original number be x.
First operation gives 2x
Second operation gives 2x 4
Third operation gives 3(2x 4)
Fourth operation gives 3(2x 4) + 28
This is equal to 10 times the original number
3(2x  4) + 28 = 10x
6x 12 + 28 = 10x
...
x = 4
Nevaeh's original number was 4.
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