Nevaeh thinks of a number.
She then does the following operations:
Multiply by 2, subtract 4, multiply by 3 then add 28 (in that order).
She finds that the number she ends up with is 10 times her original number.
What was Nevaeh's original number?
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This question is best answered by forming an algebraic equation then solving it. Let Nevaeh's original number be x.
First operation gives 2x
Second operation gives 2x- 4
Third operation gives 3(2x- 4)
Fourth operation gives 3(2x- 4) + 28
This is equal to 10 times the original number
3(2x - 4) + 28 = 10x
6x- 12 + 28 = 10x
x = 4
Nevaeh's original number was 4.
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