Jamie thinks of a number which he types into his calculator.
He then does the following operations:
Multiply by 4, subtract 5, multiply by 2 then add 5 (in that order).
He finds that the number he ends up with is 7 times his
original number.
What was Jamie's original number?
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This question is best answered by forming an algebraic equation then solving it. Let Jamie's original number be x.
First operation gives 4x
Second operation gives 4x - 5
Third operation gives 2(4x - 5)
Fourth operation gives 2(4x - 5) + 5
This is equal to seven times the original number
2(4x - 5) + 5 = 7x
8x - 10 + 5 = 7x
8x = 7x + 5
x = 5
Jamie's original number was 5.
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Teacher, do your students have
access to computers? Do you have "Laptops in Lessons"? Whether your students each have a TabletPC or share a desktop PC, this activity lends itself to eLearning (Engaged Learning). |
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Here's the URL which will take students to our eQuation Generator which provides unlimited practice solving linear equations.
http://www.transum.org/go/?to=eQuation